Skip to main content

[转]“部落格观察”推出Blog排名

并不指望我blog能如何,但是何时才有简体中文Blog排名呢?


//原文(决定以后转载都加上这个)

4月份，我曾经写过一篇“blog的价值到底该如何评估？－试谈blog排名的计算”，谈到blog价值的评估及其排名计算的方法。不过却一直没看到一家中文网站提供blog排名的服务，直到今天才偶遇到一家台湾网站“部落格观察”推出了blog排名服务，该服务对blog的成长和排名进行统计分析，只面向繁体中文和台文blog(不过经测试简体blog一样可以提交)。

输入你的blog地址，它会自动分析，然后生成这个blog的唯一ID，通过这个ID可以将blog的排名及统计情况实时显示出来，同时支持图片和文本方式，你也可以很方便的将这个排名放到你的blog上。如果你有兴趣也可以去登记一下。

从这个blog排名的排行榜上，可以看到台湾地区排名第一的blog是：弯弯～用漫画写日志，更多的blog排名可以看这里。

部落格观察推出的blog排名综合了多项搜索引擎、网摘、blog工具网站的数据，以下是排名的计算公式：

总排名=Index 指数+ 影响+ Page 总分+ Blog Influence+ Technorati 。。。

Index指数 将 Google Web Page(含 http:// 及 不含) + Google Link + Yahoo Link + Blogger Search (link 与 url 加总) 及 Technorati (link, blog, url 先加总) 先取 log 再相加
影响 将 Google 加上 Blogger 及 Technorati 的总合 然后与 Yahoo Link 相乘，再开根号
重视度 订阅人数 加 网摘人数
Page总分 将 Google Web Page (W and W/OUT http://) + Google Link + Yahoo Link +Blogger Search + Technorti
[!] 原始的 Blog Influnece 分数
Google Google 搜寻出来的 Web Page 数量 (含 http:// 及不含)
Link Google 及 Yahoo 用 link: 搜寻出来之数字
Blogger 在 Blogger 用 link 与 url 搜寻出来之数字
Technorati Technorati 的排行, Blog 连结数, 来源数与网页数 (但系统排名是经过调整)
Bloglines 透过 Bloglines 阅读 Feed (RSS, Atom, …) 的人数
Delicious 在 del.icio.us 摘录 Blog 网址的人数

从以上可以看出这个blog排名计算相当的全面，也很有参考价值，不过如果是大陆做blog排名，部分服务商需要做变更，这样才更符合大陆blog的实际情况。


Comments

Post a Comment

Popular posts from this blog

Determine Perspective Lines With Off-page Vanishing Point

In perspective drawing, a vanishing point represents a group of parallel lines, in other words, a direction. For any point on the paper, if we want a line towards the same direction (in the 3d space), we simply draw a line through it and the vanishing point. But sometimes the vanishing point is too far away, such that it is outside the paper/canvas. In this example, we have a point P and two perspective lines L1 and L2. The vanishing point VP is naturally the intersection of L1 and L2. The task is to draw a line through P and VP, without having VP on the paper. I am aware of a few traditional solutions: 1. Use extra pieces of paper such that we can extend L1 and L2 until we see VP. 2. Draw everything in a smaller scale, such that we can see both P and VP on the paper. Draw the line and scale everything back. 3. Draw a perspective grid using the Brewer Method. #1 and #2 might be quite practical. #3 may not guarantee a solution, unless we can measure distances/p...
3 comments
Read More »

Chasing an IO Phantom

My home server has been weird since months ago, it just becomes unresponsive occassionally. It is annoying but it happens only rarely, so normally I'd just wait or reboot it. But weeks ago I decided to get to the bottom of it. What's Wrong My system set up is: Root: SSD, LUKS + LVM + Ext4 Data: HDD, LUKS + ZFS 16GB RAM + 1GB swap Rootless dockerd The system may become unresponsive, when the IO on HDD  is persistantly high for a while. Also: Often kswapd0 has high CPU High IO on root fs (SSD) From dockerd and some containers RAM usage is high, swap usage is low It is very strange that IO on HDD can affect SSD. Note that when this happens, even stopping the IO on HDD does not always help. Usually restarting dockerd does not help, but rebooting helps. Investigation: Swap An obvious potential root cause is the swap. High CPU on kswapd0 usually means the free memory is low and the kernel is busy exchanging data between disk and swap. However, I tried the following steps, none of the...
Post a Comment
Read More »

Moving Items Along Bezier Curves with CSS Animation (Part 2: Time Warp)

This is a follow-up of my earlier article.  I realized that there is another way of achieving the same effect. This article has lots of nice examples and explanations, the basic idea is to make very simple @keyframe rules, usually just a linear movement, then use timing function to distort the time, such that the motion path becomes the desired curve. I'd like to call it the "time warp" hack. Demo See the Pen Interactive cubic Bezier curve + CSS animation by Lu Wang ( @coolwanglu ) on CodePen . How does it work? Recall that a cubic Bezier curve is defined by this formula : \[B(t) = (1-t)^3P_0+3(1-t)^2tP_1+3(1-t)t^2P_2+t^3P_3,\ 0 \le t \le 1.\] In the 2D case, \(B(t)\) has two coordinates, \(x(t)\) and \(y(t)\). Define \(x_i\) to the be x coordinate of \(P_i\), then we have: \[x(t) = (1-t)^3x_0+3(1-t)^2tx_1+3(1-t)t^2x_2+t^3x_3,\ 0 \le t \le 1.\] So, for our animated element, we want to make sure that the x coordiante (i.e. the "left" CSS property) is \(...
3 comments
Read More »