Skip to main content

gnome桌面便笺 | best sticky note application

最近需要搞个桌面上的todo list, 以前是用screenlets,现在不用了,而且为一个插件就开这个庞然大物太浪费了。

我在用gnote,但是这个不适合放在桌面上。gnome-panel的一个小插件也是sticky note,但是不能锁定在桌面上,一点就消失了。

另外搜到的xpad,但是我这里有bug,一个灰色的窗口,什么都么有。网上搜到了解决的patch,但是不想折腾了。

最后看到某人论坛留言: 在桌面建一个文本文件,然后把图标放大。。。顿时豁然开朗,一开始遇到这个特性时还觉得有些烦人,但是现在需要时反而想不起来了。。。

效果不错,缺点是不能弄太多文字。


Recently I found that I need a sticky note on my desktop. I used screenlets before, but not anymore now. It's a waste to enable it only for such a gadget.

Now I'm using gnote, which is rather a nice software, but it's not suitable for 'sticky' notes. There's also a stickynote applet for gnome-panel, but I don't know how to attach the notes to desktop -- every time I click somewhere, the notes disappear.

I googled some software called 'xpad', but on my computer it's nothing but a gray empty window -- an annoying bug, although I've googled a patch for this, I've got no feeling for it.

Finally I got someone's comment on some bbs -- "create a paint text file on the desktop, and then stretch the icon large enough..." -- that's it! It was quite an annoying feature to me at the first time, but now I cannot even remember it when I do need it now...

This trick works well, except for that there cannot be too many words.

Comments

Popular posts from this blog

Determine Perspective Lines With Off-page Vanishing Point

In perspective drawing, a vanishing point represents a group of parallel lines, in other words, a direction. For any point on the paper, if we want a line towards the same direction (in the 3d space), we simply draw a line through it and the vanishing point. But sometimes the vanishing point is too far away, such that it is outside the paper/canvas. In this example, we have a point P and two perspective lines L1 and L2. The vanishing point VP is naturally the intersection of L1 and L2. The task is to draw a line through P and VP, without having VP on the paper. I am aware of a few traditional solutions: 1. Use extra pieces of paper such that we can extend L1 and L2 until we see VP. 2. Draw everything in a smaller scale, such that we can see both P and VP on the paper. Draw the line and scale everything back. 3. Draw a perspective grid using the Brewer Method. #1 and #2 might be quite practical. #3 may not guarantee a solution, unless we can measure distances/p...

Chasing an IO Phantom

My home server has been weird since months ago, it just becomes unresponsive occassionally. It is annoying but it happens only rarely, so normally I'd just wait or reboot it. But weeks ago I decided to get to the bottom of it. What's Wrong My system set up is: Root: SSD, LUKS + LVM + Ext4 Data: HDD, LUKS + ZFS 16GB RAM + 1GB swap Rootless dockerd The system may become unresponsive, when the IO on HDD  is persistantly high for a while. Also: Often kswapd0 has high CPU High IO on root fs (SSD) From dockerd and some containers RAM usage is high, swap usage is low It is very strange that IO on HDD can affect SSD. Note that when this happens, even stopping the IO on HDD does not always help. Usually restarting dockerd does not help, but rebooting helps. Investigation: Swap An obvious potential root cause is the swap. High CPU on kswapd0 usually means the free memory is low and the kernel is busy exchanging data between disk and swap. However, I tried the following steps, none of the...

Moving Items Along Bezier Curves with CSS Animation (Part 2: Time Warp)

This is a follow-up of my earlier article.  I realized that there is another way of achieving the same effect. This article has lots of nice examples and explanations, the basic idea is to make very simple @keyframe rules, usually just a linear movement, then use timing function to distort the time, such that the motion path becomes the desired curve. I'd like to call it the "time warp" hack. Demo See the Pen Interactive cubic Bezier curve + CSS animation by Lu Wang ( @coolwanglu ) on CodePen . How does it work? Recall that a cubic Bezier curve is defined by this formula : \[B(t) = (1-t)^3P_0+3(1-t)^2tP_1+3(1-t)t^2P_2+t^3P_3,\ 0 \le t \le 1.\] In the 2D case, \(B(t)\) has two coordinates, \(x(t)\) and \(y(t)\). Define \(x_i\) to the be x coordinate of \(P_i\), then we have: \[x(t) = (1-t)^3x_0+3(1-t)^2tx_1+3(1-t)t^2x_2+t^3x_3,\ 0 \le t \le 1.\] So, for our animated element, we want to make sure that the x coordiante (i.e. the "left" CSS property) is \(...