Skip to main content

不能启用触摸板的临时办法 | A workaround of enabling touchpad

症状是 touchpad 可以识别，按笔记本上的启用/禁止触摸板键，屏幕上也有正确提示，但是触摸板就是不能工作。
一个可能的原因就是在windows里面禁用了，重启进ubuntu以后就出这个问题。
另外发现在禁用的情况下，按住笔记本上那个键（我这里是Fn+F7)就可以用，松开就不行。

在网上搜到的gconf的键值，观察了一下，只有按住的时候是enabled，否则是disabled了。

临时解决方案是：

gconftool-2 -t bool -s /desktop/gnome/peripherals/touchpad/touchpad_enabled "True"

运行以后笔记本上的启用/禁止键也能正常工作了。

这个估计是Xorg或者GNOME的bug。



The symptom is that although my touchpad is recognized, and when I press the enable/disable key on my keyboard, there's right notification on the screen, but my touchpad just is not working.

One possible reason is that I've disabled it in Windows, then I restarted my machine and entered Ubuntu.

Another thing I found is that only when holding the enable/disable key can I use the touchpad.

I found the corresponding key in gconf, and indeed I observed that the key is enabled only when the enable/disable key is being held.

A workaround is to run the following command.

gconftool-2 -t bool -s /desktop/gnome/peripherals/touchpad/touchpad_enabled "True"

After that the enable/disable key works well.

This must be a bug in Xorg or GNOME.
Labels:

Comments

Post a Comment

Popular posts from this blog

Determine Perspective Lines With Off-page Vanishing Point

In perspective drawing, a vanishing point represents a group of parallel lines, in other words, a direction. For any point on the paper, if we want a line towards the same direction (in the 3d space), we simply draw a line through it and the vanishing point. But sometimes the vanishing point is too far away, such that it is outside the paper/canvas. In this example, we have a point P and two perspective lines L1 and L2. The vanishing point VP is naturally the intersection of L1 and L2. The task is to draw a line through P and VP, without having VP on the paper. I am aware of a few traditional solutions: 1. Use extra pieces of paper such that we can extend L1 and L2 until we see VP. 2. Draw everything in a smaller scale, such that we can see both P and VP on the paper. Draw the line and scale everything back. 3. Draw a perspective grid using the Brewer Method. #1 and #2 might be quite practical. #3 may not guarantee a solution, unless we can measure distances/p...
2 comments
Read More »

Chasing an IO Phantom

My home server has been weird since months ago, it just becomes unresponsive occassionally. It is annoying but it happens only rarely, so normally I'd just wait or reboot it. But weeks ago I decided to get to the bottom of it. What's Wrong My system set up is: Root: SSD, LUKS + LVM + Ext4 Data: HDD, LUKS + ZFS 16GB RAM + 1GB swap Rootless dockerd The system may become unresponsive, when the IO on HDD  is persistantly high for a while. Also: Often kswapd0 has high CPU High IO on root fs (SSD) From dockerd and some containers RAM usage is high, swap usage is low It is very strange that IO on HDD can affect SSD. Note that when this happens, even stopping the IO on HDD does not always help. Usually restarting dockerd does not help, but rebooting helps. Investigation: Swap An obvious potential root cause is the swap. High CPU on kswapd0 usually means the free memory is low and the kernel is busy exchanging data between disk and swap. However, I tried the following steps, none of the...
Post a Comment
Read More »

Moving Items Along Bezier Curves with CSS Animation (Part 2: Time Warp)

This is a follow-up of my earlier article.  I realized that there is another way of achieving the same effect. This article has lots of nice examples and explanations, the basic idea is to make very simple @keyframe rules, usually just a linear movement, then use timing function to distort the time, such that the motion path becomes the desired curve. I'd like to call it the "time warp" hack. Demo See the Pen Interactive cubic Bezier curve + CSS animation by Lu Wang ( @coolwanglu ) on CodePen . How does it work? Recall that a cubic Bezier curve is defined by this formula : \[B(t) = (1-t)^3P_0+3(1-t)^2tP_1+3(1-t)t^2P_2+t^3P_3,\ 0 \le t \le 1.\] In the 2D case, \(B(t)\) has two coordinates, \(x(t)\) and \(y(t)\). Define \(x_i\) to the be x coordinate of \(P_i\), then we have: \[x(t) = (1-t)^3x_0+3(1-t)^2tx_1+3(1-t)t^2x_2+t^3x_3,\ 0 \le t \le 1.\] So, for our animated element, we want to make sure that the x coordiante (i.e. the "left" CSS property) is \(...
3 comments
Read More »